ME 82, Fall 2003
Mechanical Engineering Measurements

Dersinden örnek olarak alýnmýþtýr.

 

Dimensions, Units, Conversion Factors, and Significant Digits

Primary Dimension

Symbol

SI unit

BG unit

English unit

mass

m (sometimes M)

kg (kilogram)

slug

lbm (pound-mass)

length

L (sometimes l)

m (meter)

ft (foot)

ft (foot)

time

t (sometimes T)

s (second)

s (second)

s (second)

temperature

T (sometimes q )

K (Kelvin)

oR (degree Rankine)

R (Rankine)

electric current

I (sometimes i)

A (ampere)

A (ampere)

A (ampere)

amount of light
(luminous intensity)

C (sometimes I)

c (candela)

c (candela)

c (candela)

amount of matter

n or N (sometimes )

mol (mole)

mol (mole)

mol (mole)

Secondary Dimension

Symbol

SI unit

BG unit

English unit

force

F (sometimes f)

N (Newton = kg× m/s2)

lbf (pound-force)

lbf (pound-force)

acceleration

a

m/s2

ft/s2

ft/s2

pressure

p or P

N/m2, i.e. Pa (Pascal)

lbf/ft2 (psf)

lbf/in2 (psi) (note: 1 ft = 12 in)

energy

E (sometimes e)

J (Joule = N× m)

ft× lbf (foot pound)

ft× lbf (foot pound)

power

P

W (watt = J/s)

ft× lbf/s

ft× lbf/s

Relationship

Newton’s second law, F = m a. [Note: Bold notation indicates a vector.] By definition of the fundamental units, this yields 1 N = 1 kg× m/s2.

Conversion

 

Discussion

The above expression is dimensionless and has a value of 1. Thus it is the conversion factor with which to multiply or divide any equation to simplify the units.

 

Example

How much force (in Newtons) is required to accelerate a mass of 13.3 kg at a constant acceleration of 1.20 m/s2?

Solution:

to the right, since Fx is the x-component of vector F, and ax is the x-component of acceleration vector a.

 

Terminology

It is not proper to say that 1.00 kg equals 9.81 N, but it is proper to say that 1.00 kg weighs 9.81 N under standard earth gravity. This is obtained by utilizing Newton’s second law with gravitational acceleration, i.e.
.

 

Relationship

Newton’s second law, F = m a. [Note: Bold notation indicates a vector.] By definition of the fundamental units, this yields 1 lbf = 1 slug× ft/s2, or 1 lbf = 32.174 lbm× ft/s2.

Conversion

or or

Discussion

The above expressions are dimensionless and each has a value of 1. Thus any of them can be considered a conversion factor with which to multiply or divide any equation to simplify the units.

Example

How much force (in lbf) is required to accelerate a mass of 13.3 lbm at a constant acceleration of 1.20 ft/s2?

Solution:

to the right, since Fx is the x-component of vector F, and ax is the x-component of acceleration vector a.

Terminology

It is not proper to say that one lbm equals one lbf, but it is proper to say that one lbm weighs one lbf under standard earth gravity. This is obtained by utilizing Newton’s second law with gravitational acceleration, i.e.
.


Review of Complex Variables

Basic Definitions in the Complex Plane

Some Rules and Review